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How do I split a String based on space but take quoted substrings as one word?
Example:
Location "Welcome to india" Bangalore Channai "IT city" Mysore it should be stored in ArrayList as
Location Welcome to india Bangalore Channai IT city Mysore 
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Use method String. split() It returns an array of String, splitted by the character you specified.
You can split a String by whitespaces or tabs in Java by using the split() method of java. lang. String class. This method accepts a regular expression and you can pass a regex matching with whitespace to split the String where words are separated by spaces.
split("\\s+") will split the string into string of array with separator as space or multiple spaces. \s+ is a regular expression for one or more spaces.
split("-"); We can simply use a character/substring instead of an actual regular expression. Of course, there are certain special characters in regex which we need to keep in mind, and escape them in case we want their literal value. Once the string is split, the result is returned as an array of Strings.
Here's how:
String str = "Location \"Welcome to india\" Bangalore " + "Channai \"IT city\" Mysore"; List<String> list = new ArrayList<String>(); Matcher m = Pattern.compile("([^\"]\\S*|\".+?\")\\s*").matcher(str); while (m.find()) list.add(m.group(1)); // Add .replace("\"", "") to remove surrounding quotes. System.out.println(list); Output:
[Location, "Welcome to india", Bangalore, Channai, "IT city", Mysore] The regular expression simply says
[^"] - token starting with something other than " \S* - followed by zero or more non-space characters".+?" - a "-symbol followed by whatever, until another ".
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