Remove element from array using array_map

Question

I use array_map to validate each array element. If it does not pass the validation it should be removed from the initial array:

$array = (123, 456);

$array = array_map(function ($e){

   if( !is_numeric($e) ){
      unset($e); 
      return; //this way i get a NULL element
   }

   $return $e;

}, $array);

OUTPUT: array(3) { [0]=> int(523) [1]=> int(555) [2]=> NULL }

Of course, I could add at the end something like:

$array = array_filter($array, 'strlen');

But isn't there a way to do this within array_map ?

UPDATE

Regarding this subject, i forgot to mention a case. What if i want to unset the entire array if one element didn't pass the validation? Can this be done with array_filter , array_map or anything else? I don't want to loop through the array with a for and so on.

Answer 1

I think array_map is not designed for your needs, because it's apply a callback for each element of your array. But array_filter does :

$array = array_filter($array, function($e) {
    return is_numeric($e);
});

Or even shorter :

$array = array_filter($array, 'is_numeric');

Answer 2

If you wanted to return false in your array_map you can then apply array_filter to clean it up.

$stores = [];

$array = array_map(function ($store) {
    if ($true) {
        return [
            'name' => $store['name'],
        ];
    } else {
        return false;
    }
}, $stores);

array_filter($array);