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How can I remove the duplicate from a list in Erlang?
Suppose I have a list like:
[1,1,2,3,4,5,5,6]
How can I get:
[1,2,3,4,5,6]
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To remove the duplicates from a list, you can make use of the built-in function set(). The specialty of the set() method is that it returns distinct elements.
This is the function that is called: set_viewer_values(Value, ViewerSet) -> if ViewerSet /= empty_set -> lists:map(fun(ViewerPid) -> ViewerPid ! {self(), set_value, Value} end, ViewerSet) end.
The List is a structure used to store a collection of data items. In Erlang, Lists are created by enclosing the values in square brackets.
In Elixir and Erlang we use `list ++ [elem]` to append elements.
You could use sets, for example:
my_nonDuplicate_list1() ->
List = [1,1,2,3,4,5,5,6],
Set = sets:from_list(List),
sets:to_list(Set).
This returns [1,2,3,4,5], no more duplicates, but most likely not sorted.
Another possibility without the usage of sets would be:
my_nonDuplicate_list2() ->
List = [1,1,2,3,4,5,5,6],
lists:usort(List).
In this case it returns [1,2,3,4,5], no more duplicates and sorted.
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