Regular expression to match EOF

Question

I have some data that look like this:

john, dave, chris
rick, sam, bob
joe, milt, paul

I'm using this regex to match the names:

/(\w.+?)(\r\n|\n|,)/

Which works for the most part, but the file ends abruptly after the last word, meaning the last value doesn't end in \r\n, \n or ,. It ends with EOF. Is there a way to match EOF in regex so I can put it right in that second grouping?

Answer 1

The answer to this question is \Z took me awhile to figure it out, but it works now. Note that conversely, \A matches beginning of the whole string (as opposed to ^ and $ matching the beginning of one line).

Python:
\Z Match absolute string end

Java, C# (.NET), PHP, Perl:
\Z Match string end (before last newline if present)
\z Match absolute string end

Go:
\z Match absolute string end

All of the above:
\A Match absolute string end

Answer 2

EOF is not actually a character. If you have a multi-line string, then '$' will match the end of the string as well as the end of a line.

In Perl and its brethren, \A and \Z match the beginning and end of the string, totally ignoring line-breaks.

GNU extensions to POSIX regexes use \` and \' for the same things.