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Regular Expression Help for Date Validation - dd/mm/yyyy - PHP [duplicate]

Can someone show me the error of my ways when it comes to this regular expression:

if(preg_match("/^[0-9]{1,2}/[0-9]{1,2}/[0-9]{4}$/", $_POST["date"]) === 0) {
   echo 'error';
}

Basically I want this to display an error message each time - unless the format is correct (dd/mm/yyyy).

What am I doing wrong with the above?

Many thanks for any pointers.

-- updated regex above shortly after posting - apologies for inconvenience --

like image 881
michaelmcgurk Avatar asked Feb 15 '12 12:02

michaelmcgurk


4 Answers

I think you should escape the slashes /^[0-9]{1,2}\/[0-9]{1,2}\/[0-9]{4}$/

like image 155
iDifferent Avatar answered Nov 05 '22 01:11

iDifferent


You need to escape the slash since you are using it as regex delimiter

/^[0-9]{1,2}\/[0-9]{1,2}\/[0-9]{4}$/

or use different regex delimiters

#^[0-9]{1,2}/[0-9]{1,2}/[0-9]{4}$#
like image 40
stema Avatar answered Nov 05 '22 03:11

stema


You can also use this one:

([0-2]\d|3[0-1])\/(0\d|1[0-2])\/(19|20)\d{2}

if you want to differentiate between dates and months, but also validate only 2 centuries.

like image 35
Academia Avatar answered Nov 05 '22 02:11

Academia


I use this for checking dates

private function validate_date( $date, $empty_allowed = true ) {

    if ( empty( $date ) ) {
        return $empty_allowed;
    }

    if ( ! strpos( $date, '/' ) ) {
        return false;
    }

    if ( substr_count( $date, '/' ) !== 2 ) {
        return false;
    }

    if ( preg_match( '/(0[1-9]|1[0-9]|3[01])\/(0[1-9]|1[012])\/(2[0-9][0-9][0-9]|1[6-9][0-9][0-9])/', $date ) !== 1 ) {
        return false;
    }

    $split = explode( '/', $date );

    return checkdate( $split[1], $split[0], $split[2] );

}
like image 38
Emil Pedersen Avatar answered Nov 05 '22 03:11

Emil Pedersen