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Fatal error: Using $this when not in object context

here is the part if having error.

Fatal error: Using $this when not in object context in /pb_events.php on line 6

line 6 is: $jpp = $this->vars->data["jpp"];

function DoEvents($this) {

    global $_CONF, $_PAGE, $_TSM , $base;

    $jpp = $this->vars->data["jpp"];

    $cache["departments"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_departments]}");
    $cache["locations"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_location]}");
    $cache["names"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_names]}");
    $cache["categories"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_categories]}");

Thanks a lot! appreciate!

like image 435
designer-trying-coding Avatar asked Oct 29 '09 13:10

designer-trying-coding


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How use $this in static method in PHP?

You can't use $this inside a static function, because static functions are independent of any instantiated object. Try making the function not static. Edit: By definition, static methods can be called without any instantiated object, and thus there is no meaningful use of $this inside a static method.

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$this is a reserved keyword in PHP that refers to the calling object. It is usually the object to which the method belongs, but possibly another object if the method is called statically from the context of a secondary object.

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1 Answers

$this only makes sense in methods, not in functions

this is ok

class Foo {
     function bar() {
          $this->...

this is not

function some() {
    $this->

// edit: didn't notice he passes "$this" as parameter

advice: simply replace "$this" with "$somethingElse"

like image 170
user187291 Avatar answered Sep 21 '22 10:09

user187291