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This is my string: 50.00.00..00.00
I want to match all . except the last one, so after a replace I end up with 50000000.00
Can somebody help me with this?
286
To match any character except a list of excluded characters, put the excluded charaters between [^ and ] . The caret ^ must immediately follow the [ or else it stands for just itself. The character '. ' (period) is a metacharacter (it sometimes has a special meaning).
$ means "Match the end of the string" (the position after the last character in the string).
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
\.(?=.*\.)
Matches a dot (\.), which there must be another dot following it ((?=.*\.)).
(This assumes the regex engine supports lookahead, e.g. PCRE, Python, etc.)
168
So you did not specified your regex tools, engine, etc. Well you can do this with e.g. sed (only work if there are always two digits after the last dot and the last dot is always present):
echo "50.00.00..00.00" | sed 's/\.//;s/\(..\)$/.\1/'
But there are several other ways, e.g. with lookahead regex (if it's supported for you).
HTH
23
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