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Registering and using a custom java.net.URL protocol

I was trying to invoke a custom url from my java program, hence I used something like this:

URL myURL; try {    myURL = new URL("CustomURI:");    URLConnection myURLConnection = myURL.openConnection();    myURLConnection.connect(); } catch (Exception e) {    e.printStackTrace(); } 

I got the below exception:

java.net.MalformedURLException: unknown protocol: CustomURI at java.net.URL.(Unknown Source) at java.net.URL.(Unknown Source) at java.net.URL.(Unknown Source) at com.demo.TestDemo.main(TestDemo.java:14)

If I trigger the URI from a browser then it works as expected but if I try to invoke it from the Java Program then I am getting the above exception.

EDIT:

Below are the steps I tried (I am missing something for sure, please let me know on that):

Step 1: Adding the Custom URI in java.protocol.handler.pkgs

Step 2: Triggering the Custom URI from URL

Code:

public class CustomURI {  public static void main(String[] args) {      try {         add("CustomURI:");         URL uri = new URL("CustomURI:");         URLConnection uc = uri.openConnection();                     uc.connect();     } catch (Exception e) {         e.printStackTrace();     }  }  public static void add( String handlerPackage ){      final String key = "java.protocol.handler.pkgs";      String newValue = handlerPackage;     if ( System.getProperty( key ) != null )     {         final String previousValue = System.getProperty( key );         newValue += "|" + previousValue;     }     System.setProperty( key, newValue );     System.out.println(System.getProperty("java.protocol.handler.pkgs"));  }  } 

When I run this code, I am getting the CustomURI: printed in my console (from the add method) but then I am getting this exception when the URL is initialized with CustomURI: as a constructor:

Exception in thread "main" java.lang.StackOverflowError at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) at java.net.URL.getURLStreamHandler(Unknown Source) at java.net.URL.<init>(Unknown Source) at java.net.URL.<init>(Unknown Source) at sun.misc.URLClassPath$FileLoader.getResource(Unknown Source) at sun.misc.URLClassPath.getResource(Unknown Source) at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.net.URL.getURLStreamHandler(Unknown Source) at java.net.URL.<init>(Unknown Source) at java.net.URL.<init>(Unknown Source) 

Please advice how to make this work.

like image 904
user182944 Avatar asked Oct 14 '14 14:10

user182944


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2 Answers

  1. Create a custom URLConnection implementation which performs the job in connect() method.

    public class CustomURLConnection extends URLConnection {      protected CustomURLConnection(URL url) {         super(url);     }      @Override     public void connect() throws IOException {         // Do your job here. As of now it merely prints "Connected!".         System.out.println("Connected!");     }  } 

    Don't forget to override and implement other methods like getInputStream() accordingly. More detail on that cannot be given as this information is missing in the question.


  2. Create a custom URLStreamHandler implementation which returns it in openConnection().

    public class CustomURLStreamHandler extends URLStreamHandler {      @Override     protected URLConnection openConnection(URL url) throws IOException {         return new CustomURLConnection(url);     }  } 

    Don't forget to override and implement other methods if necessary.


  3. Create a custom URLStreamHandlerFactory which creates and returns it based on the protocol.

    public class CustomURLStreamHandlerFactory implements URLStreamHandlerFactory {      @Override     public URLStreamHandler createURLStreamHandler(String protocol) {         if ("customuri".equals(protocol)) {             return new CustomURLStreamHandler();         }          return null;     }  } 

    Note that protocols are always lowercase.


  4. Finally register it during application's startup via URL#setURLStreamHandlerFactory()

    URL.setURLStreamHandlerFactory(new CustomURLStreamHandlerFactory()); 

    Note that the Javadoc explicitly says that you can set it at most once. So if you intend to support multiple custom protocols in the same application, you'd need to generify the custom URLStreamHandlerFactory implementation to cover them all inside the createURLStreamHandler() method.


    Alternatively, if you dislike the Law of Demeter, throw it all together in anonymous classes for code minification:

    URL.setURLStreamHandlerFactory(new URLStreamHandlerFactory() {     public URLStreamHandler createURLStreamHandler(String protocol) {         return "customuri".equals(protocol) ? new URLStreamHandler() {             protected URLConnection openConnection(URL url) throws IOException {                 return new URLConnection(url) {                     public void connect() throws IOException {                         System.out.println("Connected!");                     }                 };             }         } : null;     } }); 

    If you're on Java 8 already, replace the URLStreamHandlerFactory functional interface by a lambda for further minification:

    URL.setURLStreamHandlerFactory(protocol -> "customuri".equals(protocol) ? new URLStreamHandler() {     protected URLConnection openConnection(URL url) throws IOException {         return new URLConnection(url) {             public void connect() throws IOException {                 System.out.println("Connected!");             }         };     } } : null); 

Now you can use it as follows:

URLConnection connection = new URL("CustomURI:blabla").openConnection(); connection.connect(); // ... 

Or with lowercased protocol as per the spec:

URLConnection connection = new URL("customuri:blabla").openConnection(); connection.connect(); // ... 
like image 130
BalusC Avatar answered Sep 28 '22 05:09

BalusC


If you don't want to take over the one-and-only URLStreamHandlerFactory, you can actually use a hideous, but effective naming convention to get in on the default implementation.

You must name your URLStreamHandler class Handler, and the protocol it maps to is the last segment of that class' package.

So, com.foo.myproto.Handler->myproto:urls, provided you add your package com.foo to the list of "url stream source packages" for lookup on unknown protocol. You do this via system property "java.protocol.handler.pkgs" (which is a | delimited list of package names to search).

Here is an abstract class that performs what you need: (don't mind the missing StringTo<Out1<String>> or StringURLConnection, these do what their names suggest and you can use whatever abstractions you prefer)

public abstract class AbstractURLStreamHandler extends URLStreamHandler {      protected abstract StringTo<Out1<String>> dynamicFiles();      protected static void addMyPackage(Class<? extends URLStreamHandler> handlerClass) {         // Ensure that we are registered as a url protocol handler for JavaFxCss:/path css files.         String was = System.getProperty("java.protocol.handler.pkgs", "");         String pkg = handlerClass.getPackage().getName();         int ind = pkg.lastIndexOf('.');         assert ind != -1 : "You can't add url handlers in the base package";         assert "Handler".equals(handlerClass.getSimpleName()) : "A URLStreamHandler must be in a class named Handler; not " + handlerClass.getSimpleName();          System.setProperty("java.protocol.handler.pkgs", handlerClass.getPackage().getName().substring(0, ind) +             (was.isEmpty() ? "" : "|" + was ));     }       @Override     protected URLConnection openConnection(URL u) throws IOException {         final String path = u.getPath();         final Out1<String> file = dynamicFiles().get(path);         return new StringURLConnection(u, file);     } } 

Then, here is the actual class implementing the abstract handler (for dynamic: urls:

package xapi.dev.api.dynamic;  // imports elided for brevity  public class Handler extends AbstractURLStreamHandler {      private static final StringTo<Out1<String>> dynamicFiles = X_Collect.newStringMap(Out1.class,         CollectionOptions.asConcurrent(true)             .mutable(true)             .insertionOrdered(false)             .build());      static {         addMyPackage(Handler.class);     }      @Override     protected StringTo<Out1<String>> dynamicFiles() {         return dynamicFiles;     }      public static String registerDynamicUrl(String path, Out1<String> contents) {         dynamicFiles.put(path, contents);         return path;     }      public static void clearDynamicUrl(String path) {         dynamicFiles.remove(path);     }  } 
like image 41
Ajax Avatar answered Sep 28 '22 06:09

Ajax