regex - wrap all integers in double quotes

Question

I want to turn this string;

0000,0767,"078", 0785, "0723",23487, 345 , 07334

Into this string;

"0000","0767","078", "0785", "0723","23487", "345" , "07334"

This is the closest I can get to it, I always get a bit confused with negative lookups and such when it comes to regex.

[^"\d,]?(\d+) and a replace with "$1" - https://regex101.com/r/qVQYA7/1

unfortunately this results in double wrapped quotes for integers that already have double quotes around them, like so;

"0000","0767",""078"","0785", ""0723"","23487","345" ,"07334"

The pseudo logic is; look for any integers that don't already have double quotes around them, and add double quotes. Leave any spacing in between commas as is.

Answer 1

You can simply search for "?(\d+)"? and replace it with "$1". If there are " present, they are matched but not contained in the group.

Answer 2

You can use lookarounds in your regex to avoid matching quoted numbers:

(?<!")(\b\d+\b)(?!")

Updated Regex Demo

RegEx Breakup:

(?<!")   # Negative lookbehind to skip the match if previous character is "
(        # captured group #1 open
   \b    # assert word boundary
   \d+   # match 1 or more digits
   \b    # assert word boundary
)        # captured group close
(?!")    # Negative lookahead to skip the match if next character is "

If you're using PCRE then you can use this PCRE verb:

"\d+"(*SKIP)(*F)|(\d+)