Regex to get first two words of unknown length from a string

Question

Say I have a string with various words of unknown length. I plan to split the string by using a regular expression. Something like:

String resString = origString.split(".*//s.*//s")[0];

What would be the regular expression to get the first two words? I was thinking .*//s.*//s, so all characters, followed by a space, then all characters, followed by another space. But using that gives me the exact same string I had before. Am I going about this the wrong way?

Any help would be appreciated!

Answer 1

If you have only spaces between words, split by \\s+. When you split, the array would be the words themselves. First two would be in arr[0] and arr[1] if you do:

String[] arr = origString.split("\\s+");