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Let's say you have some lines that look like this
1 int some_function() {
2 int x = 3; // Some silly comment
And so on. The indentation is done with spaces, and each indent is two spaces.
You want to change each indent to be three spaces. The simple regex
s/ {2}/ /g
Doesn't work for you, because that changes some non-indent spaces; in this case it changes the two spaces before // Some silly comment into three spaces, which is not desired. (This gets far worse if there are tables or comments aligned at the back end of the line.)
You can't simply use
/^( {2})+/
Because what would you replace it with? I don't know of an easy way to find out how many times a + was matched in a regex, so we have no idea how many altered indents to insert.
You could always go line-by-line and cut off the indents, measure them, build a new indent string, and tack it onto the line, but it would be oh so much simpler if there was a regex.
Is there a regular expression to replace indent levels as described above?
557
\s stands for “whitespace character”. Again, which characters this actually includes, depends on the regex flavor. In all flavors discussed in this tutorial, it includes [ \t\r\n\f]. That is: \s matches a space, a tab, a carriage return, a line feed, or a form feed.
The RegExp \s Metacharacter in JavaScript is used to find the whitespace characters. The whitespace character can be a space/tab/new line/vertical character. It is same as [ \t\n\r].
If you need to replace multiple spaces (double spaces) in a string to single space with C# you can use next string method: public string Replace(string oldValue, string newValue)
In some regex flavors, you can use a lookbehind:
s/(?<=^ *) / /g
In all other flavors, you can reverse the string, use a lookahead (which all flavors support) and reverse again:
s/ (?= *$)/ /g
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