Regex that matches a newline (\n) in C#

Question

OK, this one is driving me nuts.... I have a string that is formed thus:

var newContent = string.Format("({0})\n{1}", stripped_content, reply) 

newContent will display like:
(old text)
new text

I need a regular expression that strips away the text between parentheses with the parenthesis included AND the newline character.

The best I can come up with is:

const string  regex = @"^(\(.*\)\s)?(?<capture>.*)"; var match= Regex.Match(original_content, regex); var stripped_content = match.Groups["capture"].Value; 

This works, but I want specifically to match the newline (\n), not any whitespace (\s) Replacing \s with \n \\n or \\\n does NOT work.

Please help me hold on to my sanity!

EDIT: an example:

public string Reply(string old,string neww)         {             const string  regex = @"^(\(.*\)\s)?(?<capture>.*)";             var match= Regex.Match(old, regex);             var stripped_content = match.Groups["capture"].Value;             var result= string.Format("({0})\n{1}", stripped_content, neww);             return result;         }  Reply("(messageOne)\nmessageTwo","messageThree") returns : (messageTwo) messageThree 

Answer 1

If you specify RegexOptions.Multiline then you can use ^ and $ to match the start and end of a line, respectively.

If you don't wish to use this option, remember that a new line may be any one of the following: \n, \r, \r\n, so instead of looking only for \n, you should perhaps use something like: [\n\r]+, or more exactly: (\n|\r|\r\n).

Answer 2

Actually it works but with opposite option i.e.

 RegexOptions.Singleline