regex match bash variable

Question

I am trying to modify a bash script. The script current contains

print "<div class=\"title\">" $1 "</div>"

Where $1 may look like:

Apprentice Historian (Level 1)
Historian (Level 4)
Master Historian (Level 7)

What i'd like to do is add an image which is named the "base" value. I had something like this in mind:

print "<div class=\"icon\"><imgsrc=\"icons\" $1 ".png\"></div><div class=\"title\">" $1 "</div>"

However, in this case I'd like $1 to only return Historian. I was thinking I could use a regex to match and on $1 and keep only the part I need.

(Apprentice|Master)?\s(.*)\s(\(Level \d\)) 

I know my regex isn't quite there, ideally apprentice/master would be in their own match group and not tied the base. And I don't know how to match on the $1 argument.

Answer 1

Using regex matching in bash:

for a in 'Apprentice Historian (Level 1)' 'Historian (Level 4)' 'Master Historian (Level 7)' ; do
    set "$a"
    echo " === $1 ==="
    [[ $1 =~ (Apprentice|Master)?' '?(.*)' ('Level' '[0-9]+')' ]] \
        && echo ${BASH_REMATCH[${#BASH_REMATCH[@]}-1]}
done 

The tricky part is to retrieve the correct member from BASH_REMATCH. Bash does not support non-capturing parentheses, therefore Historian is either under 1 or 2. Fortunately, we know it is the last one.