Menu
I checked on stackoverflow already but didn't find a solution I could use. I need a regular expression to match any word (by word I mean anything between full spaces) that contains numbers. It can be alphanumeric AB12354KFJKL, or dates 11/01/2014, or numbers with hyphens in the middle, 123-489-568, or just plain normal numbers 123456789 - but it can't match anything without numbers. Thanks,
Better example of what I want (in bold) in a sample text:
ABC1 ABC 23-4787 ABCD 4578 ABCD 11/01/2014 ABREKF
475
Since regular expressions work with text, a regular expression engine treats 0 as a single character, and 255 as three characters. To match all characters from 0 to 255, we'll need a regex that matches between one and three characters. The regex [0-9] matches single-digit numbers 0 to 9.
$ means "Match the end of the string" (the position after the last character in the string). Both are called anchors and ensure that the entire string is matched instead of just a substring.
To match any number from 0 to 9 we use \d in regex. It will match any single digit number from 0 to 9. \d means [0-9] or match any number from 0 to 9. Instead of writing 0123456789 the shorthand version is [0-9] where [] is used for character range.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
There must be something better, but I think this should work:
\S*\d+\S*
\S* - Zero or more non-whitespace characters
\d+ - One or more digits
\S* - Zero or more non-whitespace characters
71
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
