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I am trying to create a regex that will return false if the String pattern contains whitespace or is empty. So far I have this
[^\s] I think that will make sure the string does not contain whitespace but I am unsure of how to also check to make sure it is not empty. Any help would be appreciated.
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Non-whitespace character: \S.
In regex, the uppercase metacharacter is always the inverse of the lowercase counterpart. \d (digit) matches any single digit (same as [0-9] ). The uppercase counterpart \D (non-digit) matches any single character that is not a digit (same as [^0-9] ).
Example: "a\+" matches "a+" and not a series of one or "a"s. ^ the caret is the anchor for the start of the string, or the negation symbol. Example: "^a" matches "a" at the start of the string. Example: "[^0-9]" matches any non digit.
Match Whitespace Characters in Python? Yes, the dot regex matches whitespace characters when using Python's re module.
/^$|\s+/ if this matched, there's whitespace or its empty.
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In my understanding you want to match a non-blank and non-empty string, so the top answer is doing the opposite. I suggest:
(.|\s)*\S(.|\s)* This matches any string containing at least one non-whitespace character (the \S in the middle). It can be preceded and followed by anything, any character or whitespace sequence (including new lines): (.|\s)*.
You can try it with explanation on regex101.
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