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var alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; How can I remove everything between H and S so that the outcome would be ABCDEFGHSTUVWXYZ?
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To use RegEx, the first argument of replace will be replaced with regex syntax, for example /regex/ . This syntax serves as a pattern where any parts of the string that match it will be replaced with the new substring. The string 3foobar4 matches the regex /\d. *\d/ , so it is replaced.
Use the deleteCharAt Method to Remove a Character From String in Java. The deleteCharAt() method is a member method of the StringBuilder class that can also be used to remove a character from a string in Java.
Using replaceAll() The first parameter takes in a regular expression while the second takes in a string with the replacement value. String start = "\\{"; String end = "\\}"; String updatedUrl = url. replaceAll(start + ". *" + end, "*");
var alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; console.log( alphabet.replace(/H.*S/, 'HS') )Or just:
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