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Regex for Mobile Number Validation

I want a regex for mobile number validation. The regex pattern should be such that it must accept + only in beginning and space(or -) should be allowed only after country code(only once). Only 10 digit number should be allowed after the country code. The country code should be optional. If country code doesn't exist, it should accept only 10 digit number. Regex should prevent any invalid number like (eg:+91 0000000000 or 0000000000).

The regex should accept numbers like

  • +1 8087339090
  • +91 8087339090
  • +912 8087339090
  • 8087339090
  • 08087339090
  • +1-8087339090
  • +91-8087339090
  • +912-8087339090
  • +918087677876(Country code(2 digits) + 10 digits Mobile Number)
  • +9108087735454(Country code(3 digits) + 10 digits Mobile Number)

The regex should not accept numbers like

  • ++51 874645(double successive +)
  • +71 84364356(double successive spaces)
  • +91 808 75 74 678(not more than one space)
  • +91 808-75-74-678(not more than one -)
  • +91-846363
  • 80873(number less than 10 digit)
  • 8087339090456(number greater than 10 digit)
  • 0000000000(all zeros)
  • +91 0000000(all zeros with country code)
like image 533
Ashu6767 Avatar asked Mar 13 '14 12:03

Ashu6767


2 Answers

Satisfies all your requirements if you use the trick told below

Regex: /^(\+\d{1,3}[- ]?)?\d{10}$/

  1. ^ start of line
  2. A + followed by \d+ followed by a or - which are optional.
  3. Whole point two is optional.
  4. Negative lookahead to make sure 0s do not follow.
  5. Match \d+ 10 times.
  6. Line end.

DEMO Added multiline flag in demo to check for all cases

P.S. You really need to specify which language you use so as to use an if condition something like below:

// true if above regex is satisfied and (&&) it does not (`!`) match `0`s `5` or more times  if(number.match(/^(\+\d{1,3}[- ]?)?\d{10}$/) && ! (number.match(/0{5,}/)) ) 
like image 179
Gaurang Tandon Avatar answered Sep 24 '22 21:09

Gaurang Tandon


This regex is very short and sweet for working.

/^([+]\d{2})?\d{10}$/

Ex: +910123456789 or 0123456789

-> /^ and $/ is for starting and ending
-> The ? mark is used for conditional formatting where before question mark is available or not it will work
-> ([+]\d{2}) this indicates that the + sign with two digits '\d{2}' here you can place digit as per country
-> after the ? mark '\d{10}' this says that the digits must be 10 of length change as per your country mobile number length

This is how this regex for mobile number is working.
+ sign is used for world wide matching of number.

if you want to add the space between than you can use the

[ ]

here the square bracket represents the character sequence and a space is character for searching in regex.
for the space separated digit you can use this regex

/^([+]\d{2}[ ])?\d{10}$/

Ex: +91 0123456789

Thanks ask any question if you have.

like image 23
Nishit Zinzuvadiya Avatar answered Sep 24 '22 21:09

Nishit Zinzuvadiya