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Reference detection in array from another function

So I'm using the pin method, but the reference is detected one level too late:

$pin = time();

function wrap($arr){
  test($arr);
}

function test(&$arr){
    global $pin;

    if(in_array($pin, $arr))
        return print "ref";

    $arr[] = $pin;

    foreach($arr as &$v){

        if($v != $pin){

            if(is_array($v))
                return test($v);

            print $v . " ";

      }

    }

}

$array = array(1, 2, 3);
$array[4] = &$array;

wrap($array);

I get 1 2 3 1 2 3 rec

But I expect 1 2 3 rec

If I just do test($arr) then it works, but the problem is that I need to wrap the test function inside another one that accepts values not references :(

Is there any way I can detect the reference at the right moment with my wrapper function too?

like image 316
Alex Avatar asked Apr 03 '13 00:04

Alex


2 Answers

Introduction

I think a better approach would be to create a copy of the array and compare modification rather than use global pin and it can still be a 100% Recursive

Example 1

This is from your example above :

$array = array(1,2,3);
$array[4] = &$array;
wrap($array);

Output

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [4] => ref
)

Example 2

Are we really sure its detecting reference or just a copy of the array

//Case 1 : Expect no modification
$array = array(1, 2, 3, array(1, 2, 3));
wrap( $array);

//Case 2 : Expect Modification in Key 2
$array = array(1, 2, 3, array(1, 2, 3));
$array[2] = &$array;
wrap( $array);

Output

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
        )

)
Array
(
    [0] => 1
    [1] => 2
    [2] => ref
    [3] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
        )

)

Example 3

Is this really recursive ?

$array = array(1, 2, 3, array(1, 2, 3));
$array[4][4][2][6][1] = array(1,2,3=>&$array);
wrap( $array);

Output

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [3] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
        )

    [4] => Array
        (
            [4] => Array
                (
                    [2] => Array
                        (
                            [6] => Array
                                (
                                    [1] => Array
                                        (
                                            [0] => 1
                                            [1] => 2
                                            [3] => ref   <-- GOT YOU
                                        )

                                )

                        )

                )

        )

)

Your Modified Function

/**
 * Added printf since test now returns array
 * @param array $arr
 */
function wrap(array $arr) {
    printf("<pre>%s<pre>", print_r(test($arr), true));
}


/**
 * - Removed Top Refrence
 * - Removed Global
 * - Add Recursion
 * - Returns array
 * @param array $arr
 * @return array
 */
function test(array $arr) {
    $temp = $arr;
    foreach ( $arr as $key => &$v ) {
        if (is_array($v)) {
            $temp[$key]['_PIN_'] = true;
            $v = isset($arr[$key]['_PIN_']) ? "ref" : test($v);
        }
    }
    unset($temp); // cleanup
    return $arr;
}
like image 173
Baba Avatar answered Sep 28 '22 02:09

Baba


I think you are over-complicating things. I solved this by looping over the array and checking if the current value in the array is equivalent (===) with the array.

function wrap( $arr){
    test($arr);
}

function test( $arr){
    foreach( $arr as $v) {
        if( $v === $arr) { 
            print 'ref, ';
        } else {
            if( is_array( $v)) { 
                test( $v); 
            } else {
                print $v . ', ';
            }
        }
    }
}

I used the following test cases:

echo "Array 1:\n";
$array1 = array(1, 2, 3);
$array1[4] = &$array1;
wrap( $array1);

echo "\nArray 2:\n";
$array2 = array(1, 2, 3, array(1, 2, 3));
$array2[2] = &$array2;
wrap( $array2);

Which produced this output:

Array 1: 
1, 2, 3, ref 
Array 2: 
1, 2, ref, 1, 2, 3, 

However, the above method will fail for nested references. If nested references are possible, as in the following test case:

echo "\nArray 3:\n";
$array3 = array(1, 2, 3, array(1, 2, 3));
$array3[3][2] = &$array3;
wrap( $array3);

Then we need to keep track of all the array references we've seen, like this:

function wrap( $arr){
    test( $arr);
}

function test( $arr){
    $refs = array(); // Array of references that we've seen

    $f = function( $arr) use( &$refs, &$f) {
        $refs[] = $arr;
        foreach( $arr as $v) {
            if( in_array( $v, $refs)) { 
                print 'ref, ';
            } else {
                if( is_array( $v)) {
                    $f( $v); 
                } else {
                    print $v . ', ';
                }
            }
        }
    };
    $f( $arr);
}

Using the above test case, this outputs:

Array 3: 
1, 2, 3, 1, ref, 3,

Edit: I've updated the final function that keeps track of all references to eliminate the global dependencies.

like image 40
nickb Avatar answered Sep 28 '22 01:09

nickb