Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Redshift: Serializable isolation violation on table

I have a very large Redshift database that contains billions of rows of HTTP request data.

I have a table called requests which has a few important fields:

  • ip_address
  • city
  • state
  • country

I have a Python process running once per day, which grabs all distinct rows which have not yet been geocoded (do not have any city / state / country information), and then attempts to geocode each IP address via Google's Geocoding API.

This process (pseudocode) looks like this:

for ip_address in ips_to_geocode:
    country, state, city = geocode_ip_address(ip_address)
    execute_transaction('''
        UPDATE requests
        SET ip_country = %s, ip_state = %s, ip_city = %s
        WHERE ip_address = %s
    ''')

When running this code, I often receive errors like the following:

psycopg2.InternalError: 1023
DETAIL:  Serializable isolation violation on table - 108263, transactions forming the cycle are: 647671, 647682 (pid:23880)

I'm assuming this is because I have other processes constantly logging HTTP requests into my table, so when I attempt to execute my UPDATE statement, it is unable to select all rows with the ip address I'd like to update.

My question is this: what can I do to update these records in a sane way that will stop failing regularly?

like image 340
rdegges Avatar asked Jan 20 '16 22:01

rdegges


2 Answers

Your code is violating the serializable isolation level of Redshift. You need to make sure that your code is not trying to open multiple transactions on the same table before closing all open transactions.

You can achieve this by locking the table in each transaction so that no other transaction can access the table for updates until the open transaction gets closed. Not sure how your code is architected (synchronous or asynchronous), but this will increase the run time as each lock will force others to wait till the transaction gets over.

Refer: http://docs.aws.amazon.com/redshift/latest/dg/r_LOCK.html

like image 100
Paladin Avatar answered Sep 22 '22 23:09

Paladin


Just got the same issue on my code, and this is how I fixed it:

First things first, it is good to know that this error code means you are trying to do concurrent operations in redshift. When you do a second query to a table before the first query you did moments ago was done, for example, is a case where you would get this kind of error (that was my case).

Good news is: there is a simple way to serialize redshift operations! You just need to use the LOCK command. Here is the Amazon documentation for the redshift LOCK command. It works basically making the next operation wait until the previous one is closed. Note that, using this command your script will naturally get a little bit slower.

In the end, the practical solution for me was: I inserted the LOCK command before the query messages (in the same string, separated by a ';'). Something like this:

LOCK table_name; SELECT * from ...

And you should be good to go! I hope it helps you.

like image 43
Marcus Vinicius Melo Avatar answered Sep 18 '22 23:09

Marcus Vinicius Melo