Redis Python - how to delete all keys according to a specific pattern In python, without python iterating

Question

I'm writing a django management command to handle some of our redis caching. Basically, I need to choose all keys, that confirm to a certain pattern (for example: "prefix:*") and delete them.

I know I can use the cli to do that:

redis-cli KEYS "prefix:*" | xargs redis-cli DEL 

But I need to do this from within the app. So I need to use the python binding (I'm using py-redis). I have tried feeding a list into delete, but it fails:

from common.redis_client import get_redis_client cache = get_redis_client() x = cache.keys('prefix:*')   x == ['prefix:key1','prefix:key2'] # True 

# And now

cache.delete(x)  

# returns 0 . nothing is deleted

I know I can iterate over x:

for key in x:    cache.delete(key) 

But that would be losing redis awesome speed and misusing its capabilities. Is there a pythonic solution with py-redis, without iteration and/or the cli?

Thanks!

Answer 1

Use SCAN iterators: https://pypi.python.org/pypi/redis

for key in r.scan_iter("prefix:*"):     r.delete(key)