Redirect to a url with query string in Django

Question

How can I go to a specific URL with parameters like if I have view

def search(request): 

and in urls.py

^search/$  

and what I need to do is to redirect like search/?item=4

c = {} render_to_response("search.html",c)  

works fine, but

render_to_response("search.html/?item=" + itemID, c ) 

it says no template found ( I know there is no template like search.html/?item= ) but how can I pass parameters or use query string to redirect?

Answer 1

Using reverse and passing the name of url we can redirect to url with query string:

#urls.py

url(r'^search/$', views.search, name='search_view') 

#views.py

from django.shortcuts import redirect, reverse  # in method return redirect(reverse('search_view') + '?item=4') 

Answer 2

I know this question is a bit old, but someone will stumble upon this while searching redirect with query string, so here is my solution:

import urllib from django.shortcuts import redirect  def redirect_params(url, params=None):     response = redirect(url)     if params:         query_string = urllib.urlencode(params)         response['Location'] += '?' + query_string     return response  def your_view(request):     your_params = {         'item': 4     }     return redirect_params('search_view', your_params)