I looked around a lot before posting this question so my apologies if it is on another post and this is only my second quesiton on here so apologies if I don't format this question correctly.
I have a really simple web service that I have created that needs to take post values and return a JSON encoded array. That all worked fine until I was told I would need to post the form data with a content-type of application/json. Since then I cannot return any values from the web service and it is definitely something to do with how I am filtering their post values.
Basically in my local setup I have created a test page that does the following -
$curl = curl_init(); curl_setopt($curl, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($curl, CURLOPT_POSTFIELDS, $data); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HTTPHEADER, array( 'Content-Type: application/json', 'Content-Length: ' . strlen($data)) ); curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/'); // Set the url path we want to call $result = curl_exec($curl); //see the results $json=json_decode($result,true); curl_close($curl); print_r($json);
On the webservice I have this (I have stripped out some of the functions) -
<?php header('Content-type: application/json'); /* connect to the db */ $link = mysql_connect('localhost','root','root') or die('Cannot connect to the DB'); mysql_select_db('webservice',$link) or die('Cannot select the DB'); if(isset($_POST['action']) && $_POST['action'] == 'login') { $statusCode = array('statusCode'=>1, 'statusDescription'=>'Login Process - Fail'); $posts[] = array('status'=>$statusCode); header('Content-type: application/json'); echo json_encode($posts); /* disconnect from the db */ } @mysql_close($link); ?>
Basically I know that it is due to the $_POST values not being set but I can't find what I need to put instead of the $_POST. I tried json_decode($_POST), file_get_contents("php://input") and a number of other ways but I was shooting in the dark a bit.
Any help would be greatly appreciated.
Thanks, Steve
Thanks Michael for the help, that was a definite step forward I now have at least got a repsonse when I echo the post....even if it is null
updated CURL -
$curl = curl_init(); curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: application/json')); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/'); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POSTFIELDS, json_encode($data));
updated php on the page that the data is posted to -
$inputJSON = file_get_contents('php://input'); $input= json_decode( $inputJSON, TRUE ); //convert JSON into array print_r(json_encode($input));
As I say at least I see a response now wheras prior it was returning a blank page
Reading JSON From a File or String in PHP First, you need to get the data from the file into a variable by using file_get_contents() . Once the data is in a string, you can call the json_decode() function to extract information from the string.
JSON stands for the JavaScript Object Notation. It is used to exchanging and storing the data from the web-server. JSON uses the object notation of JavaScript. JavaScript objects can be converted into the JSON and receive JSON format text into the JavaScript objects.
You have empty $_POST
. If your web-server wants see data in json-format you need to read the raw input and then parse it with JSON decode.
You need something like that:
$json = file_get_contents('php://input'); $obj = json_decode($json);
Also you have wrong code for testing JSON-communication...
CURLOPT_POSTFIELDS
tells curl
to encode your parameters as application/x-www-form-urlencoded
. You need JSON-string here.
UPDATE
Your php code for test page should be like that:
$data_string = json_encode($data); $ch = curl_init('http://webservice.local/'); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_HTTPHEADER, array( 'Content-Type: application/json', 'Content-Length: ' . strlen($data_string)) ); $result = curl_exec($ch); $result = json_decode($result); var_dump($result);
Also on your web-service page you should remove one of the lines header('Content-type: application/json');
. It must be called only once.
Hello this is a snippet from an old project of mine that uses curl to get ip information from some free ip databases services which reply in json format. I think it might help you.
$ip_srv = array("http://freegeoip.net/json/$this->ip","http://smart-ip.net/geoip-json/$this->ip"); getUserLocation($ip_srv);
Function:
function getUserLocation($services) { $ctx = stream_context_create(array('http' => array('timeout' => 15))); // 15 seconds timeout for ($i = 0; $i < count($services); $i++) { // Configuring curl options $options = array ( CURLOPT_RETURNTRANSFER => true, // return web page //CURLOPT_HEADER => false, // don't return headers CURLOPT_HTTPHEADER => array('Content-type: application/json'), CURLOPT_FOLLOWLOCATION => true, // follow redirects CURLOPT_ENCODING => "", // handle compressed CURLOPT_USERAGENT => "test", // who am i CURLOPT_AUTOREFERER => true, // set referer on redirect CURLOPT_CONNECTTIMEOUT => 5, // timeout on connect CURLOPT_TIMEOUT => 5, // timeout on response CURLOPT_MAXREDIRS => 10 // stop after 10 redirects ); // Initializing curl $ch = curl_init($services[$i]); curl_setopt_array ( $ch, $options ); $content = curl_exec ( $ch ); $err = curl_errno ( $ch ); $errmsg = curl_error ( $ch ); $header = curl_getinfo ( $ch ); $httpCode = curl_getinfo ( $ch, CURLINFO_HTTP_CODE ); curl_close ( $ch ); //echo 'service: ' . $services[$i] . '</br>'; //echo 'err: '.$err.'</br>'; //echo 'errmsg: '.$errmsg.'</br>'; //echo 'httpCode: '.$httpCode.'</br>'; //print_r($header); //print_r(json_decode($content, true)); if ($err == 0 && $httpCode == 200 && $header['download_content_length'] > 0) { return json_decode($content, true); } } }
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