Reading from file using read() function

Question

I have to write a program that reads numbers in separate lines each. Is it possible to read only one line of the file and then read an int from the buffer, and so on until the end of file? It is really hard to find good examples of using read and write. My example is kind of working but I'd like to read until it detects '\n' char and then convert buffer into int.

#include <fcntl.h> 
#include <stdio.h> 
#include <string.h>
#include <unistd.h> 
#include <iostream>

int fd[2];

void readFile(int fd) {
    unsigned char buffer[10];
    int bytes_read;
    int k=0;
    do {
        bytes_read = read(fd, buffer, 10); 
        k++;
            for(int i=0; i<10; i++) {
            printf("%c", buffer[i]);
        }
    }
    while (bytes_read != 0); 
}

int tab[50];

int main(int argc, char *argv[]) {
    if(argv[1] == NULL || argv[2] == NULL)   {
            printf("Function requires two arguments!\nGood bye...\n");
            return -1;
    }
    else {
        if (access(argv[1], F_OK) == 0) {
            fd[0] = open(argv[1], O_RDONLY);
        }
        else { 
            fd[0] = open(argv[1], O_WRONLY|O_CREAT|O_SYNC, 0700);
            const int size = 50;
                for(int i=0; i<size; i++) {
                    char buf[10];   
                    sprintf(buf, "%d\n", i+1);
                    write(fd[0], buf, strlen(buf));
                }
                close(fd[0]);
            fd[0] = open(argv[1], O_RDONLY);
            if (access(argv[2], F_OK) == 0) 
                fd[1] = open(argv[2], O_WRONLY);
            else 
                fd[1] = open(argv[2], O_WRONLY|O_CREAT, 0700);
        }
    }

    if (access(argv[2], F_OK) == 0) 
        fd[1] = open(argv[2], O_WRONLY); 
    else 
        fd[1] = open(argv[2], O_WRONLY|O_CREAT, 0700);


    readFile(fd[0]);
    close(fd[0]);
    close(fd[1]);
}

Revised code:

void readFile(int fd) {
    char buffer[10];
    int bytes_read;
    int k = 0;
    do {
        char t = 0;
        bytes_read = read(fd, &t, 1); 
        buffer[k++] = t;    
        printf("%c", t);
        if(t == '\n' && t == '\0') {
            printf("%d", atoi(buffer));
            for(int i=0; i<10; i++) 
                buffer[i]='\0';
            k = 0;
        }
    }
    while (bytes_read != 0); 
}

Answer 1

Read Byte by Byte and check that each byte against '\n' if it is not, then store it into buffer
if it is '\n' add '\0' to buffer and then use atoi()

You can read a single byte like this

char c;
read(fd,&c,1);

See read()