I would like to read a resource from within my jar like so:
File file; file = new File(getClass().getResource("/file.txt").toURI()); BufferedReader reader = new BufferedReader(new FileReader(file)); //Read the file
and it works fine when running it in Eclipse, but if I export it to a jar, and then run it, there is an IllegalArgumentException:
Exception in thread "Thread-2" java.lang.IllegalArgumentException: URI is not hierarchical
and I really don't know why but with some testing I found if I change
file = new File(getClass().getResource("/file.txt").toURI());
to
file = new File(getClass().getResource("/folder/file.txt").toURI());
then it works the opposite (it works in jar but not eclipse).
I'm using Eclipse and the folder with my file is in a class folder.
This works when running inside and outside of a Jar file. PathMatchingResourcePatternResolver r = new PathMatchingResourcePatternResolver(); Resource[] resources = r. getResources("/myfolder/*"); Then you can access the data using getInputStream and the filename from getFilename .
Install an archive program. JAR files work just like ZIP files. You can use any archive program to extract them. On Windows, you can Install WinRAR 7-Zip, or WinZIP.
Hi, Jar files are archive files that contains of a lot of different java classes (files). You can use winzip/winrar to open the jar files and you can see those java classes in jar files. Typically you can use a Java decompiler to decompile the class file and look into the source code.
Rather than trying to address the resource as a File just ask the ClassLoader to return an InputStream for the resource instead via getResourceAsStream:
try (InputStream in = getClass().getResourceAsStream("/file.txt"); BufferedReader reader = new BufferedReader(new InputStreamReader(in))) { // Use resource }
As long as the file.txt
resource is available on the classpath then this approach will work the same way regardless of whether the file.txt
resource is in a classes/
directory or inside a jar
.
The URI is not hierarchical
occurs because the URI for a resource within a jar file is going to look something like this: file:/example.jar!/file.txt
. You cannot read the entries within a jar
(a zip
file) like it was a plain old File.
This is explained well by the answers to:
To access a file in a jar you have two options:
Place the file in directory structure matching your package name (after extracting .jar file, it should be in the same directory as .class file), then access it using getClass().getResourceAsStream("file.txt")
Place the file at the root (after extracting .jar file, it should be in the root), then access it using Thread.currentThread().getContextClassLoader().getResourceAsStream("file.txt")
The first option may not work when jar is used as a plugin.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With