Flask sends form data to template Flask to send form data to the template we have seen that http method can be specified in the URL rule. Form data received by the trigger function can be collected in the form of a dictionary object and forwarded to the template to render it on the corresponding web page.
FileStorage
contains stream
field. This object must extend IO or file object, so it must contain read
and other similar methods. FileStorage
also extend stream
field object attributes, so you can just use file.read()
instead file.stream.read()
. Also you can use save
argument with dst
parameter as StringIO
or other IO or file object to copy FileStorage.stream
to another IO or file object.
See documentation: http://flask.pocoo.org/docs/api/#flask.Request.files and http://werkzeug.pocoo.org/docs/datastructures/#werkzeug.datastructures.FileStorage.
If you want to use standard Flask stuff - there's no way to avoid saving a temporary file if the uploaded file size is > 500kb. If it's smaller than 500kb - it will use "BytesIO", which stores the file content in memory, and if it's more than 500kb - it stores the contents in TemporaryFile() (as stated in the werkzeug documentation). In both cases your script will block until the entirety of uploaded file is received.
The easiest way to work around this that I have found is:
1) Create your own file-like IO class where you do all the processing of the incoming data
2) In your script, override Request class with your own:
class MyRequest( Request ):
def _get_file_stream( self, total_content_length, content_type, filename=None, content_length=None ):
return MyAwesomeIO( filename, 'w' )
3) Replace Flask's request_class with your own:
app.request_class = MyRequest
4) Go have some beer :)
I was trying to do the exact same thing, open a text file (a CSV for Pandas actually). Don't want to make a copy of it, just want to open it. The form-WTF has a nice file browser, but then it opens the file and makes a temporary file, which it presents as a memory stream. With a little work under the hood,
form = UploadForm()
if form.validate_on_submit():
filename = secure_filename(form.fileContents.data.filename)
filestream = form.fileContents.data
filestream.seek(0)
ef = pd.read_csv( filestream )
sr = pd.DataFrame(ef)
return render_template('dataframe.html',tables=[sr.to_html(justify='center, classes='table table-bordered table-hover')],titles = [filename], form=form)
I share my solution (assuming everything is already configured to connect to google bucket in flask)
from google.cloud import storage
@app.route('/upload/', methods=['POST'])
def upload():
if request.method == 'POST':
# FileStorage object wrapper
file = request.files["file"]
if file:
os.environ["GOOGLE_APPLICATION_CREDENTIALS"] = app.config['GOOGLE_APPLICATION_CREDENTIALS']
bucket_name = "bucket_name"
storage_client = storage.Client()
bucket = storage_client.bucket(bucket_name)
# Upload file to Google Bucket
blob = bucket.blob(file.filename)
blob.upload_from_string(file.read())
My post
Direct to Google Bucket in flask
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With