react-icons apply a linear gradient

Question

I would like to dynamically, partially fill a react-icons sourced Font Awesome Star using linear gradient. I have tried the following:

React Component with Inline Style - Setting the background of the parent span to gradient and making the SVG transparent. Can't seem to set the border around the SVG star to #FFFFFF so I see the parent span's whole background. See below:

import React from 'react'
import FaStar from 'react-icons/lib/fa/star'

const Stars = () => {

  const inlineStyle = (pctFill) => {
    return(
      {background: 'linear-gradient(90deg, #134758 '+pctFill+'%, #d3d3d3 '+pctFill+'%)'}
    )
  }

  return(
    <div>
      <span style={inlineStyle(50)}>
        <FaStar />
      </span>
    </div>
  )
}

export default Stars

I have also tried creating a linearGradient component and setting the path's fill="url(#component)", but react-icons path is the 3rd child to my parent span which I can't figure out how to access.

Please help

Answer 1

Was having the same issue, here's a simple working solution:

1. Add a < svg > element wrapping a < gradient > element to the component.

2. Add an id to the < gradient >

3. Link the gradient to the "stroke" property of the icon via "url(< id >)":

import { FiCheck } from 'react-icons/fi';

//...

<svg width="0" height="0">
  <linearGradient id="blue-gradient" x1="100%" y1="100%" x2="0%" y2="0%">
    <stop stopColor="#7a6ded" offset="0%" />
    <stop stopColor="#591885" offset="100%" />
  </linearGradient>
</svg>


<FiCheck style={{ stroke: "url(#blue-gradient)" }} />

obs: In some packs you may need to switch "stroke" to "fill".

Answer 2

  <svg width="1em" height="1em">
  <linearGradient id="blue-gradient" x1="100%" y1="100%" x2="0%" y2="0%">
    <stop stopColor="#7a6ded" offset="0%" />
    <stop stopColor="#591885" offset="100%" />
  </linearGradient>

<FaFacebook style={{ fill: "url(#blue-gradient)"}}/>

My code worked in this way. Thanks a lot.