Randomly generated hexadecimal number in C#

Question

How can I generate a random hexadecimal number with a length of my choice using C#?

Answer 1

static Random random = new Random(); public static string GetRandomHexNumber(int digits) {     byte[] buffer = new byte[digits / 2];     random.NextBytes(buffer);     string result = String.Concat(buffer.Select(x => x.ToString("X2")).ToArray());     if (digits % 2 == 0)         return result;     return result + random.Next(16).ToString("X"); } 

Answer 2

    Random random = new Random();     int num = random.Next();     string hexString = num.ToString("X"); 

random.Next() takes arguments that let you specify a min and a max value, so that's how you would control the length.