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Random double generation between a range in dart

Tags:

flutter

dart

Need to generate random doubles between a range

The nextint() function takes a param max where as the nextdouble() doesnt take any params. Is there any other methods that return random doubles between a range in dart?

like image 795
strek Avatar asked Dec 05 '19 09:12

strek


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3 Answers

The nextDouble returns a value between 0 and 1 (not included). So, if you want a number in the range a (included) to b (not included), you can just do:

double doubleInRange(Random source, num start, num end) => 
    source.nextDouble() * (end - start) + start;

print(doubleInRange(random, a, b));
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lrn Avatar answered Oct 16 '22 11:10

lrn


No, there isn't, but it easy to recreate it since nextInt takes only a max value (exclusive).

nextDouble() * max

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pr0gramist Avatar answered Oct 16 '22 09:10

pr0gramist


I doubt there is. If you want just double values you can convert the integer value to double

import 'dart:math';

main() {
var rng = new Random();
for (var i = 0; i < 10; i++) {
print(rng.nextInt(100).toDouble());
}}

If you want the type of double values generated by nextDouble() such as '0.2502033576383784' i suggest you create a function to handle the range of values.

import 'dart:math';

main() {
var rng = new Random();
for (var i = 0; i < 10; i++) {
print(rng.nextDouble()+rng.nextInt(50));
}}
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Tomisin Avatar answered Oct 16 '22 09:10

Tomisin