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Rails 3: alias_method_chain still used?

I was just reading about Gems/Plugin development for Rails 3 and ran across this post that says that alias_method_chain is no longer used. I can see the method is still there in activesupport-3.0.0/lib/active_support/core_ext/module/aliasing.rb.

Should I still be using alias_method_chain in Rails 3?

Is this still reflective of the best practices for gems/plugins in Rails 3 that want to modify ActiveRecord?

like image 873
mikewilliamson Avatar asked Sep 11 '10 03:09

mikewilliamson


2 Answers

No, it has been replaced by a clever use of method overriding in modules and the super keyword.

Basically, you define the original function in an included module, and override it in another included module. When you call super in the overriding function, it calls the original function. But there is one catch. You have to include the extending modules after including the base module, and in the order you want the chaining to occur.

class Something
  module Base  
    def my_method
      # (A) original functionality
    end
  end

  module PreExtension
    def my_method
      # (B) before the original
      super # calls whatever was my_method before this definition was made
    end
  end

  module PostExtension
    def my_method
      super # calls whatever was my_method before this definition was made
      # (C) after the original
    end
  end

  include Base # this is needed to place the base methods in the inheritance stack
  include PreExtension # this will override the original my_method
  include PostExtension # this will override my_method defined in PreExtension
end

s = Something.new
s.my_method 
#=> this is a twice extended method call that will execute code in this order:
#=> (B) before the original
#=> (A) the original
#=> (C) after the original

Ryan Bates of Railscasts talks about how this is used in the Rails Routing code. I'd recommend watching it, and his other screencasts. They have the power to transform a knitting grandmother into a Rails guru.

PS: Credit goes to Peeja for correcting a fundamental error in my original answer. Thanks.

like image 80
edgerunner Avatar answered Nov 07 '22 14:11

edgerunner


In general, a module can never override a method in the class it's included in. This is because module inclusion works just like subclassing. A superclass can't override its subclasses' methods either, nor would you expect it to.

When a module is included in a class, the module is inserted just after the class in the class's ancestor chain. Calling super from the class will call the module's implementation.

class Something
  module PreExtension; end
  module PostExtension; end

  include PreExtension
  include PostExtension
end

Something.ancestors # => [Something, Something::PostExtension, Something::PreExtension, Object, Kernel]

Whenever a method is called on a Something, Ruby looks through this list in order and calls the first implementation it finds. If the implementation calls super, it keeps looking and finds the next one.

This means that modules included later take precedence over modules included earlier, and can call super to get the earlier modules' implementations. This is because included modules are inserted in the ancestor chain directly after the class. This is how the routing code edgerunner mentioned works. That code puts everything in modules, like so:

class SomethingNew
  module Base
    def my_method
      puts "(A)"
    end
  end

  module Extension
    def my_method
      puts "(B)"
      super
    end
  end

  include Base
  include Extension
end

SomethingNew.new.my_method
# Output:
# >> (B)
# >> (A)

SomethingNew.ancestors # => [SomethingNew, SomethingNew::Extension, SomethingNew::Base, Object, Kernel]

This is why alias_method_chain existed in the first place. If putting the base code in a module is not an option, I'm not sure how to accomplish the equivalent of alias_method_chain.

like image 19
Peeja Avatar answered Nov 07 '22 14:11

Peeja