I have a data frame holding information on options like this
> chData
myIdx strike_price date exdate cp_flag strike_price return
1 8355342 605000 1996-04-02 1996-05-18 P 605000 0.002340
2 8355433 605000 1996-04-02 1996-05-18 C 605000 0.002340
3 8356541 605000 1996-04-09 1996-05-18 P 605000 -0.003182
4 8356629 605000 1996-04-09 1996-05-18 C 605000 -0.003182
5 8358033 605000 1996-04-16 1996-05-18 P 605000 0.003907
6 8358119 605000 1996-04-16 1996-05-18 C 605000 0.003907
7 8359391 605000 1996-04-23 1996-05-18 P 605000 0.005695
where cp_flag means that a certain option is either a call or a put. What is a way to make sure that for each date, there is a both a call and a put, and drop the rows for which this does not exist? I can do it with a for loop, but is there a more clever way?
Get the dates that have P's and those that have C's, and use intersect to find the dates that have both.
keep_dates <- with(x, intersect(date[cp_flag=='P'], date[cp_flag=='C']) )
# "1996-04-02" "1996-04-09" "1996-04-16"
Keep only the rows that have dates appearing in keep_dates.
x[ x$date %in% keep_dates, ]
# myIdx strike_price date exdate cp_flag strike_price.1
# 8355342 605000 1996-04-02 1996-05-18 P 605000
# 8355433 605000 1996-04-02 1996-05-18 C 605000
# 8356541 605000 1996-04-09 1996-05-18 P 605000
# 8356629 605000 1996-04-09 1996-05-18 C 605000
# 8358033 605000 1996-04-16 1996-05-18 P 605000
# 8358119 605000 1996-04-16 1996-05-18 C 605000
Using the plyr
package:
> ddply(chData, "date", function(x) if(all(c("P","C") %in% x$cp_flag)) x)
myIdx strike_price date exdate cp_flag strike_price.1 return
1 8355342 605000 1996-04-02 1996-05-18 P 605000 0.002340
2 8355433 605000 1996-04-02 1996-05-18 C 605000 0.002340
3 8356541 605000 1996-04-09 1996-05-18 P 605000 -0.003182
4 8356629 605000 1996-04-09 1996-05-18 C 605000 -0.003182
5 8358033 605000 1996-04-16 1996-05-18 P 605000 0.003907
6 8358119 605000 1996-04-16 1996-05-18 C 605000 0.003907
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