I've search a while and still can not figure it out... Here's part of my code that went wrong.
import subprocess as sp
import os
cmd_args = []
cmd_args.append('start ')
cmd_args.append('/wait ')
cmd_args.append(os.path.join(dirpath,filename))
print(cmd_args)
child = sp.Popen(cmd_args)
And the command prompt through out this.
['start ', '/wait ', 'C:\\Users\\xxx\\Desktop\\directory\\myexecutable.EXE']
Traceback (most recent call last):
File "InstallALL.py", line 89, in <module>
child = sp.Popen(cmd_args)
File "C:\Python34\lib\subprocess.py", line 859, in __init__
restore_signals, start_new_session)
File "C:\Python34\lib\subprocess.py", line 1114, in _execute_child startupinfo)
FileNotFoundError: [WinError 2]
It looks like the filepath is wrong with 2 backslashes.
I know if I do
print(os.path.join(dirpath,filename))
It'll return
C:\Users\xxx\Desktop\directory\myexecutable.EXE
I'm sure the file is there. How can I debug this?
The recommended approach to invoking subprocesses is to use the run() function for all use cases it can handle. For more advanced use cases, the underlying Popen interface can be used directly. Run the command described by args. Wait for command to complete, then return a CompletedProcess instance.
Python method popen() opens a pipe to or from command. The return value is an open file object connected to the pipe, which can be read or written depending on whether mode is 'r' (default) or 'w'. The bufsize argument has the same meaning as in open() function.
There the connection is not closed. So you do not need to close most probably. unrelated: you could use stdin=open('test. sql', 'rb', 0) to redirect child's stdin from the file without loading the whole file into your Python process first.
After reading the docs, I came to know that shell=True means executing the code through the shell. So that means in absence, the process is directly started.
This is happening because Popen
is trying to find the file start
instead of the file you want to run.
For example, using notepad.exe
:
>>> import subprocess
>>> subprocess.Popen(['C:\\Windows\\System32\\notepad.exe', '/A', 'randomfile.txt']) # '/A' is a command line option
<subprocess.Popen object at 0x03970810>
This works fine. But if I put the path at the end of the list:
>>> subprocess.Popen(['/A', 'randomfile.txt', 'C:\\Windows\\System32\\notepad.exe'])
Traceback (most recent call last):
File "<pyshell#53>", line 1, in <module>
subprocess.Popen(['/A', 'randomfile.txt', 'C:\\Windows\\System32\\notepad.exe'])
File "C:\python35\lib\subprocess.py", line 950, in __init__
restore_signals, start_new_session)
File "C:\python35\lib\subprocess.py", line 1220, in _execute_child
startupinfo)
FileNotFoundError: [WinError 2] The system cannot find the file specified
Use this instead:
import subprocess as sp
import os
cmd_args = []
cmd_args.append(os.path.join(dirpath,filename))
cmd_args.append('start ')
cmd_args.append('/wait ')
print(cmd_args)
child = sp.Popen(cmd_args)
You might need to swap cmd_args.append('start ')
and cmd_args.append('/wait ')
around too depending on which order they are meant to be in.
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