Python, create shortcut with two paths and argument

Question

I'm trying to create a shortcut through python that will launch a file in another program with an argument. E.g:

"C:\file.exe" "C:\folder\file.ext" argument

The code I've tried messing with:

from win32com.client import Dispatch
import os

shell = Dispatch("WScript.Shell")
shortcut = shell.CreateShortCut(path)

shortcut.Targetpath = r'"C:\file.exe" "C:\folder\file.ext"'
shortcut.Arguments = argument
shortcut.WorkingDirectory = "C:\" #or "C:\folder\file.ext" in this case?
shortcut.save()

But i get an error thrown my way:

AttributeError: Property '<unknown>.Targetpath' can not be set.

I've tried different formats of the string and google doesn't seem to know the solution to this problem

Answer 1

from comtypes.client import CreateObject
from comtypes.gen import IWshRuntimeLibrary

shell = CreateObject("WScript.Shell")
shortcut = shell.CreateShortCut(path).QueryInterface(IWshRuntimeLibrary.IWshShortcut)

shortcut.TargetPath = "C:\file.exe"
args = ["C:\folder\file.ext", argument]
shortcut.Arguments = " ".join(args)
shortcut.Save()

Reference