Python time differences

Question

I have two time objects.

Example

time.struct_time(tm_year=2010, tm_mon=9, tm_mday=24, tm_hour=19, tm_min=13, tm_sec=37, tm_wday=4, tm_yday=267, tm_isdst=-1)  time.struct_time(tm_year=2010, tm_mon=9, tm_mday=25, tm_hour=13, tm_min=7, tm_sec=25, tm_wday=5, tm_yday=268, tm_isdst=-1) 

I want to have the difference of those two. How could I do that? I need minutes and seconds only, as well as the duration of those two.

Answer 1

Time instances do not support the subtraction operation. Given that one way to solve this would be to convert the time to seconds since epoch and then find the difference, use:

>>> t1 = time.localtime() >>> t1 time.struct_time(tm_year=2010, tm_mon=10, tm_mday=13, tm_hour=10, tm_min=12, tm_sec=27, tm_wday=2, tm_yday=286, tm_isdst=0) >>> t2 = time.gmtime() >>> t2 time.struct_time(tm_year=2010, tm_mon=10, tm_mday=13, tm_hour=4, tm_min=42, tm_sec=37, tm_wday=2, tm_yday=286, tm_isdst=0)  >>> (time.mktime(t1) - time.mktime(t2)) / 60 329.83333333333331 

Answer 2

>>> t1 = time.mktime(time.strptime("10 Oct 10", "%d %b %y")) >>> t2 = time.mktime(time.strptime("15 Oct 10", "%d %b %y")) >>> print(datetime.timedelta(seconds=t2-t1)) 5 days, 0:00:00