python sys.exit not working in try [duplicate]

Question

Python 2.7.5 (default, Feb 26 2014, 13:43:17) [GCC 4.4.7 20120313 (Red Hat 4.4.7-4)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> try: ...  sys.exit() ... except: ...  print "in except" ... in except >>> try: ...  sys.exit(0) ... except: ...  print "in except" ... in except >>> try: ...  sys.exit(1) ... except: ...  print "in except" ... in except 

Why am not able to trigger sys.exit() in try, any suggestions...!!!

The code posted here has all the version details.

I have tried all possible ways i know to trigger it, but i failed. It gets to 'except' block.

Thanks in advance..

Answer 1

sys.exit() raises an exception, namely SystemExit. That's why you land in the except-block.

See this example:

import sys  try:     sys.exit() except:     print(sys.exc_info()[0]) 

This gives you:

<type 'exceptions.SystemExit'> 

Although I can't imagine that one has any practical reason to do so, you can use this construct:

import sys  try:     sys.exit() # this always raises SystemExit except SystemExit:     print("sys.exit() worked as expected") except:     print("Something went horribly wrong") # some other exception got raised