I have a list
of custom-class objects (sample is below).
Using: list(itertools.chain.from_iterable(myBigList))
I wanted to "merge" all of the stations
sublists into one big list. So I thought I need to make my custom class an iterable.
Here is a sample of my custom class.
class direction(object) : def __init__(self, id) : self.id = id self.__stations = list() def __iter__(self): self.__i = 0 # iterable current item return iter(self.__stations) def __next__(self): if self.__i<len(self.__stations)-1: self.__i += 1 return self.__stations[self.__i] else: raise StopIteration
I implemented __iter__
and __next__
but it doesn't seems to work. They're not even called.
Any idea what could I've done wrong?
Note: Using Python 3.3
To make the range object iterable (and thus let for..of work) we need to add a method to the object named Symbol. iterator (a special built-in symbol just for that). When for..of starts, it calls that method once (or errors if not found). The method must return an iterator – an object with the method next .
To make your class Iterable we need to override __iter__() function inside our class i.e. This function should return the object of Iterator class associated with this Iterable class. Contains List of Junior and senior team members and also overrides the __iter__() function. It overrides the __iter__() function.
The iterable protocol allows JavaScript objects to define or customize their iteration behavior, such as what values are looped over in a for...of construct. Some built-in types are built-in iterables with a default iteration behavior, such as Array or Map , while other types (such as Object ) are not.
The Python "TypeError: 'type' object is not iterable" occurs when we try to iterate over a class that is not iterable, e.g. forget to call the range() function. To solve the error, make the class iterable by implementing the __iter__() method.
__iter__
is what gets called when you try to iterate over a class instance:
>>> class Foo(object): ... def __iter__(self): ... return (x for x in range(4)) ... >>> list(Foo()) [0, 1, 2, 3]
__next__
is what gets called on the object which is returned from __iter__
(on python2.x, it's next
, not __next__
-- I generally alias them both so that the code will work with either...):
class Bar(object): def __init__(self): self.idx = 0 self.data = range(4) def __iter__(self): return self def __next__(self): self.idx += 1 try: return self.data[self.idx-1] except IndexError: self.idx = 0 raise StopIteration # Done iterating. next = __next__ # python2.x compatibility.
In the comments, it was asked how you would construct and object that could be iterated multiple times. In this case, I'd recommend taking the same approach that Python takes and split the iterator from the data container:
class BarIterator(object): def __init__(self, data_sequence): self.idx = 0 self.data = data_sequence def __iter__(self): return self def __next__(self): self.idx += 1 try: return self.data[self.idx-1] except IndexError: self.idx = 0 raise StopIteration # Done iterating. class Bar(object): def __init__(self, data_sequence): self.data_sequence = data_sequence def __iter__(self): return BarIterator(self.data_sequence)
simply implementing __iter__
should be enough.
class direction(object) : def __init__(self, id) : self.id = id self.__stations = list() def __iter__(self): #return iter(self.__stations[1:]) #uncomment this if you wanted to skip the first element. return iter(self.__stations) a = direction(1) a._direction__stations= range(5) b = direction(1) b._direction__stations = range(10) import itertools print list(itertools.chain.from_iterable([a,b])) print list(itertools.chain.from_iterable([range(5),range(10)]))
output:
[0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
See here for why it's _direction__stations
Any identifier of the form __spam (at least two leading underscores, at most one trailing underscore) is textually replaced with classname_spam, where classname is the current class name with leading underscore(s) stripped.
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