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Python String Cleanup + Manipulation (Accented Characters)

I have a database full of names like:

John Smith  
Scott J. Holmes  
Dr. Kaplan  
Ray's Dog  
Levi's  
Adrian O'Brien  
Perry Sean Smyre  
Carie Burchfield-Thompson  
Björn Árnason

There are a few foreign names with accents in them that need to be converted to strings with non-accented characters.

I'd like to convert the full names (after stripping characters like " ' " , "-") to user logins like:

john.smith  
scott.j.holmes  
dr.kaplan  
rays.dog  
levis
adrian.obrien  
perry.sean.smyre
carie.burchfieldthompson  
bjorn.arnason

So far I have:

Fullname.strip()  # get rid of leading/trailing white space
Fullname.lower() # make everything lower case


... # after bad chars converted/removed
Fullname.replace(' ', '.') # replace spaces with periods
like image 638
GeekJock Avatar asked May 30 '09 18:05

GeekJock


1 Answers

Take a look at this link [redacted]

Here is the code from the page

def latin1_to_ascii (unicrap):
    """This replaces UNICODE Latin-1 characters with
    something equivalent in 7-bit ASCII. All characters in the standard
    7-bit ASCII range are preserved. In the 8th bit range all the Latin-1
    accented letters are stripped of their accents. Most symbol characters
    are converted to something meaningful. Anything not converted is deleted.
    """
    xlate = {
        0xc0:'A', 0xc1:'A', 0xc2:'A', 0xc3:'A', 0xc4:'A', 0xc5:'A',
        0xc6:'Ae', 0xc7:'C',
        0xc8:'E', 0xc9:'E', 0xca:'E', 0xcb:'E',
        0xcc:'I', 0xcd:'I', 0xce:'I', 0xcf:'I',
        0xd0:'Th', 0xd1:'N',
        0xd2:'O', 0xd3:'O', 0xd4:'O', 0xd5:'O', 0xd6:'O', 0xd8:'O',
        0xd9:'U', 0xda:'U', 0xdb:'U', 0xdc:'U',
        0xdd:'Y', 0xde:'th', 0xdf:'ss',
        0xe0:'a', 0xe1:'a', 0xe2:'a', 0xe3:'a', 0xe4:'a', 0xe5:'a',
        0xe6:'ae', 0xe7:'c',
        0xe8:'e', 0xe9:'e', 0xea:'e', 0xeb:'e',
        0xec:'i', 0xed:'i', 0xee:'i', 0xef:'i',
        0xf0:'th', 0xf1:'n',
        0xf2:'o', 0xf3:'o', 0xf4:'o', 0xf5:'o', 0xf6:'o', 0xf8:'o',
        0xf9:'u', 0xfa:'u', 0xfb:'u', 0xfc:'u',
        0xfd:'y', 0xfe:'th', 0xff:'y',
        0xa1:'!', 0xa2:'{cent}', 0xa3:'{pound}', 0xa4:'{currency}',
        0xa5:'{yen}', 0xa6:'|', 0xa7:'{section}', 0xa8:'{umlaut}',
        0xa9:'{C}', 0xaa:'{^a}', 0xab:'<<', 0xac:'{not}',
        0xad:'-', 0xae:'{R}', 0xaf:'_', 0xb0:'{degrees}',
        0xb1:'{+/-}', 0xb2:'{^2}', 0xb3:'{^3}', 0xb4:"'",
        0xb5:'{micro}', 0xb6:'{paragraph}', 0xb7:'*', 0xb8:'{cedilla}',
        0xb9:'{^1}', 0xba:'{^o}', 0xbb:'>>',
        0xbc:'{1/4}', 0xbd:'{1/2}', 0xbe:'{3/4}', 0xbf:'?',
        0xd7:'*', 0xf7:'/'
    }

    r = ''
    for i in unicrap:
        if xlate.has_key(ord(i)):
            r += xlate[ord(i)]
        elif ord(i) >= 0x80:
            pass
        else:
            r += i
    return r

# This gives an example of how to use latin1_to_ascii().
# This creates a string will all the characters in the latin-1 character set
# then it converts the string to plain 7-bit ASCII.
if __name__ == '__main__':
s = unicode('','latin-1')
for c in range(32,256):
    if c != 0x7f:
        s = s + unicode(chr(c),'latin-1')
print 'INPUT:'
print s.encode('latin-1')
print
print 'OUTPUT:'
print latin1_to_ascii(s)
like image 163
Bobby Avatar answered Oct 14 '22 10:10

Bobby