Pandas: How to find percentage of group members type per subgroup?

Question

(Data sample and attempts at the end of the question)

With a dataframe such as this:

    Type    Class   Area    Decision
0   A       1       North   Yes
1   B       1       North   Yes
2   C       2       South   No
3   A       3       South   No
4   B       3       South   No
5   C       1       South   No
6   A       2       North   Yes
7   B       3       South   Yes
8   B       1       North   No
9   C       1       East    No
10  C       2       West    Yes 

How can I find what percentage of each type [A, B, C, D] that belongs to each area [North, South, East, West]?

Desired output:

    North   South   East    West
A   0.66    0.33    0       0
B   0.5     0.5     0       0
C   0       0.5     0.25    0.25

My best attempt so far is:

df_attempt1= df.groupby(['Area', 'Type'])['Type'].aggregate('count').unstack().T

Which returns:

Area  East  North  South  West
Type                          
A      NaN    2.0    1.0   NaN
B      NaN    2.0    2.0   NaN
C      1.0    NaN    2.0   1.0

And I guess I can build on that by calculating sums in the margins and appending 0 for missing observations, but I'd really appreciate suggestions for more elegant approaches.

Thank you for any suggestions!

Code:

import pandas as pd

df = pd.DataFrame(
    {
        "Type": {0: "A", 1: "B", 2: "C", 3: "A", 4: "B", 5: "C", 6: "A", 7: "B", 8: "B", 9: "C", 10: "C"},
        "Class": {0: 1, 1: 1, 2: 2, 3: 3, 4: 3, 5: 1, 6: 2, 7: 3, 8: 1, 9: 1, 10: 2},
        "Area": {0: "North", 1: "North", 2: "South", 3: "South", 4: "South", 5: "South", 6: "North", 7: "South", 8: "North", 9: "East", 10: "West"},
        "Decision": {0: "Yes", 1: "Yes", 2: "No", 3: "No", 4: "No", 5: "No", 6: "Yes", 7: "Yes", 8: "No", 9: "No", 10: "Yes"},
    }
)

dfg = df[['Area', 'Type']].groupby(['Area']).agg('count').unstack()

df_attempt1 = df.groupby(['Area', 'Type'])['Type'].aggregate('count').unstack().T

Answer 1

You can use the function crosstab:

pd.crosstab(index=df['Type'], columns=df['Area'], normalize='index')

Output:

Area  East     North     South  West
Type                                
A     0.00  0.666667  0.333333  0.00
B     0.00  0.500000  0.500000  0.00
C     0.25  0.000000  0.500000  0.25

Answer 2

You were quite close already. The following should do the trick:

df.groupby('Type')['Area'].value_counts(normalize = True).unstack(fill_value=0)

Output:

Area    East    North       South       West
Type                
A       0.00    0.666667    0.333333    0.00
B       0.00    0.500000    0.500000    0.00
C       0.25    0.000000    0.500000    0.25

If order matters, you can reorder the dataframe manipulating it's columns attribute