Menu
I have a dict (which is also a key of a larger dict) of dicts that looks like
wd[wc][dist][True]={'course': {'#': 1, 'Fisher': 4.0},
'i': {'#': 1, 'Fisher': -0.2222222222222222},
'of': {'#': 1, 'Fisher': 2.0},
'will': {'#': 1, 'Fisher': 3.5}}
I want to sort the key words (at the highest level) by their corresponding 'Fisher' value... so that the output looks like
wd[wc][dist][True]={'course': {'Fisher': 4.0, '#': 1}, 'will': {'Fisher': 3.5, '#': 1}, 'of': {'Fisher': 2.0, '#': 1}, 'i': {'Fisher': -0.2222222222222222, '#': 1}}
I've tried working with items() and sorted() but can't work it out... Please help me out :(
766
To sort a list of dictionaries according to the value of the specific key, specify the key parameter of the sort() method or the sorted() function. By specifying a function to be applied to each element of the list, it is sorted according to the result of that function. See the following article for more information.
Well, as of python 3.7, dictionaries remember the order of items inserted as well. Thus we are also able to sort dictionaries using python's built-in sorted() function. Just like with other iterables, we can sort dictionaries based on different criteria depending on the key argument of the sorted() function.
It is not possible to sort a dictionary, only to get a representation of a dictionary that is sorted. Dictionaries are inherently orderless, but other types, such as lists and tuples, are not. So you need an ordered data type to represent sorted values, which will be a list—probably a list of tuples.
You can't sort a dict, but can get a sorted list of keys, values or (key,values) pairs.
>>> dic = {'i': {'Fisher': -0.2222222222222222, '#': 1}, 'of': {'Fisher': 2.0, '#': 1}, 'will': {'Fisher': 3.5, '#': 1}, 'course': {'Fisher': 4.0, '#': 1}}
>>> sorted(dic.items(), key=lambda x: x[1]['Fisher'], reverse=True)
[('course', {'Fisher': 4.0, '#': 1}),
('will', {'Fisher': 3.5, '#': 1}),
('of', {'Fisher': 2.0, '#': 1}),
('i', {'Fisher': -0.2222222222222222, '#': 1})
]
Or create an collections.OrderedDict(introduced in Python 2.7) after getting the sorted (key,value) pairs:
>>> from collections import OrderedDict
>>> od = OrderedDict(sorted(dic.items(), key=lambda x: x[1]['Fisher'], reverse=True))
>>> od
OrderedDict([
('course', {'Fisher': 4.0, '#': 1}),
('will', {'Fisher': 3.5, '#': 1}),
('of', {'Fisher': 2.0, '#': 1}),
('i', {'Fisher': -0.2222222222222222, '#': 1})
])
For your dictionary, try this:
>>> from collections import OrderedDict
>>> dic = wd[wc][dist][True]
>>> wd[wc][dist][True]= OrderedDict(sorted(dic.items(), key=lambda x: x[1]['Fisher'], reverse=True))
If you just need the keys in order, you can get a list like this
dic = {'i': {'Fisher': -0.2222222222222222, '#': 1}, 'of': {'Fisher': 2.0, '#': 1}, 'will': {'Fisher': 3.5, '#': 1}, 'course': {'Fisher': 4.0, '#': 1}}
sorted(dic, key=lambda k: dic[k]['Fisher'])
if 'Fisher' might be missing, you can use this to move those entries last
sorted(dic, key=lambda x:dic[x].get('Fisher', float('inf')))
or '-inf' to place them at the beginning
24
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
