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I believe that re.sub() is replacing the Full Match, but in this case I only want to replace the matching groups and ignore the non-capturing groups. How can I go about this?
string = 'aBCDeFGH'
print(re.sub('(a)?(?:[A-Z]{3})(e)?(?:[A-Z]{3})', '+', string))
output is :
+
Expected output is:
+BCD+FGH
483
Put a capture group around the part that you want to preserve, and then include a reference to that capture group within your replacement text. @Amber: I infer from your answer that unlike str. replace(), we can't use variables a) in raw strings; or b) as an argument to re. sub; or c) both.
sub() function belongs to the Regular Expressions ( re ) module in Python. It returns a string where all matching occurrences of the specified pattern are replaced by the replace string. To use this function, we need to import the re module first.
Non-capturing groups are important constructs within Java Regular Expressions. They create a sub-pattern that functions as a single unit but does not save the matched character sequence. In this tutorial, we'll explore how to use non-capturing groups in Java Regular Expressions.
The REGEXREPLACE( ) function uses a regular expression to find matching patterns in data, and replaces any matching values with a new string. standardizes spacing in character data by replacing one or more spaces between text characters with a single space.
The general solution for such problems is using a lambda in the replacement:
string = 'aBCDeFGH'
print(re.sub('(a)?([A-Z]{3})(e)?([A-Z]{3})', lambda match: '+%s+%s' % (match.group(2), match.group(4)), string))
However, as bro-grammer has commented, you can use backreferences in this case:
print(re.sub('(a)?([A-Z]{3})(e)?([A-Z]{3})', r'+\2+\4', string))
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