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This is written in Python,
import re
s='1 89059809102/30589533 IronMan 30 Santa Ana Massage table / IronMan 30 Santa Ana Massage table'
pattern='\s(\d{11})/(\d{8})'
re.match(pattern,s)
it returns none.
I tried taking the brackets off,
pattern='\s\d{11}/\d{8}'
It still returns none.
My questions are:
468
match() function of re in Python will search the regular expression pattern and return the first occurrence. The Python RegEx Match method checks for a match only at the beginning of the string. So, if a match is found in the first line, it returns the match object.
There is a difference between the use of both functions. Both return the first match of a substring found in the string, but re. match() searches only from the beginning of the string and return match object if found.
The match method returns a corresponding match object instance if zero or more characters at the beginning of the string match the regular expression pattern. In simple words, the re. match returns a match object only if the pattern is located at the beginning of the string; otherwise, it will return None.
A repeat is an expression that is repeated an arbitrary number of times. An expression followed by '*' can be repeated any number of times, including zero. An expression followed by '+' can be repeated any number of times, but at least once.
re.match "matches" since the beginning of the string, but there is an extra 1.
Use re.search instead, which will "search" anywhere within the string. And, in your case, also find something:
>>> re.search(pattern,s).groups()
('89059809102', '30589533')
If you remove the brackets in pattern, it will still return a valid _sre.SRE_Match, object, but with empty groups:
>>> re.search('\s\d{11}/\d{8}',s).groups()
()
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