Fairly new to Python, still struggling with so much information.
All the documentation I've seen about dictionaries explain various ways of getting a value via a key - but I'm looking for a pythonic way to do the opposite - get a key via a value.
I know I can loop through the keys and inspect their values until I find the value I'm looking for and then grab the key, but I'm looking for a direct route.
We can also fetch the key from a value by matching all the values using the dict. item() and then print the corresponding key to the given value.
Creating a Dictionary To do that you separate the key-value pairs by a colon(“:”). The keys would need to be of an immutable type, i.e., data-types for which the keys cannot be changed at runtime such as int, string, tuple, etc. The values can be of any type.
Using has_key() method returns true if a given key is available in the dictionary, otherwise, it returns a false. With the Inbuilt method has_key(), use the if statement to check if the key is present in the dictionary or not.
To simply check if a key exists in a Python dictionary you can use the in operator to search through the dictionary keys like this: pets = {'cats': 1, 'dogs': 2, 'fish': 3} if 'dogs' in pets: print('Dogs found!') # Dogs found! A dictionary can be a convenient data structure for counting the occurrence of items.
There is no direct route. It's pretty easy with list comprehensions, though;
[k for k, v in d.iteritems() if v == desired_value]
If you need to do this occasionally and don't think it's worth while indexing it the other way as well, you could do something like:
class bidict(dict):
    def key_with_value(self, value, default=None):
        for k, v in self.iteritems():
            if v == value:
                return v
        return default
    def keys_with_value(self, value, default=None):
        return [v for k, v in self.iteritems() if v == value]
Then d.key_with_value would behave rather like d.get, except the other way round.
You could also make a class which indexed it both ways automatically. Key and value would both need to be hashable, then. Here are three ways it could be implemented:
In two separate dicts, with the exposing some dict-like methods; you could perhaps do foo.by_key[key] or foo.by_value[value]. (No code given as it's more complicated and I'm lazy and I think this is suboptimal anyway.)
In a different structure, so that you could do d[key] and d.inverse[value]:
class bidict(dict):
    def __init__(self, *args, **kwargs):
        self.inverse = {}
        super(bidict, self).__init__(key, value)
    def __setitem__(self, key, value):
        super(bidict, self).__setitem__(key, value)
        self.inverse[value] = key
    def __delitem__(self, key):
        del self.inverse[self[key]]
        super(bidict, self).__delitem__(key)
In the same structure, so that you could do d[key] and d[value]:
class bidict(dict):
    def __setitem__(self, key, value):
        super(bidict, self).__setitem__(key, value)
        super(bidict, self).__setitem__(value, key)
    def __delitem__(self, key):
        super(bidict, self).__delitem__(self[key])
        super(bidict, self).__delitem__(key)
(Notably absent from these implementations of a bidict is the update method which will be slightly more complex (but help(dict.update) will indicate what you'd need to cover). Without update, bidict({1:2}) wouldn't do what it was intended to, nor would d.update({1:2}).)
Also consider whether some other data structure would be more appropriate.
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