Python regex to match a specific word

Question

I want to match all lines in a test report, which contain words 'Not Ok'. Example line of text :

'Test result 1: Not Ok -31.08'

I tried this:

filter1 = re.compile("Not Ok")
for line in myfile:                                     
    if filter1.match(line): 
       print line

which should work according to http://rubular.com/, but I get nothing at the output. Any idea, what might be wrong? Tested various other parameters, like "." and "^Test" , which work perfectly.

Answer 1

You should use re.search here not re.match.

From the docs on re.match:

If you want to locate a match anywhere in string, use search() instead.

If you're looking for the exact word 'Not Ok' then use \b word boundaries, otherwise if you're only looking for a substring 'Not Ok' then use simple : if 'Not Ok' in string.

>>> strs = 'Test result 1: Not Ok -31.08'
>>> re.search(r'\bNot Ok\b',strs).group(0)
'Not Ok'
>>> match = re.search(r'\bNot Ok\b',strs)
>>> if match:
...     print "Found"
... else:
...     print "Not Found"
...     
Found

Answer 2

You could simply use,

if <keyword> in str:
    print('Found keyword')

Example:

if 'Not Ok' in input_string:
    print('Found string')

Answer 3

Absolutely no need to use RegEx in this case! Just use:

s = 'Test result 1: Not Ok -31.08'
if s.find('Not Ok') > 0 : 
    print("Found!")

or as already mentioned:

if 'Not Ok' in s:
    print("Found!")