Python regex subsitution: separate backreference from digit [duplicate]

Question

In a regex replacement pattern, a backreference looks like \1. If you want to include a digit after that backreference, this will fail because the digit is considered to be part of the backreference number:

# replace all twin digits by zeroes, but retain white space in between
re.sub(r"\d(\s*)\d", r"0\10", "0 1")
>>> sre_constants.error: invalid group reference

Substitution pattern r"0\1 0" would work fine but in the failing example back-reference \1 is interpreted as \10.

How can the digit '0' be separated from the back-reference \1 that precedes it?

Answer 1

You can use \g<1>, as mentioned in the docs.