Python , Printing Hex removes first 0?

Question

take a look at this:

fc = '0x'
for i in b[0x15c:0x15f]:
    fc += hex(ord(i))[2:]

Lets say this code found the hex 00 04 0f , instead of writing it that way , it removes the first 0 , and writes : 04f any help?

Answer 1

>>> map("{:02x}".format, (10, 13, 15))
['0a', '0d', '0f']

Answer 2

This is happening because hex() will not include any leading zeros, for example:

>>> hex(15)[2:]
'f'

To make sure you always get two characters, you can use str.zfill() to add a leading zero when necessary:

>>> hex(15)[2:].zfill(2)
'0f'

Here is what it would look like in your code:

fc = '0x'
for i in b[0x15c:0x15f]:
    fc += hex(ord(i))[2:].zfill(2)