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I have a server and I am trying to build a post request to get the data back. I think one way to achieve this is to add the parameters in the header and make the request. But I am getting few errors that I don't understand well enough to go forward.
Html Form
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=ISO-8859-1">
</head>
<body>
<form method="POST" action="http://some.server.com:61235/imgdigest" enctype="multipart/form-data">
quality:<input type="text" name="quality" value="2"><br>
category:<input type="text" name="category" value="1"><br>
debug:<input type="text" name="debug" value="1"><br>
image:<input type="file" name="image"><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
Python code: I have edited the question based on the answer
import urllib, urllib2
import base64
if __name__ == '__main__':
page = 'http://some.site.com:61235/'
with open("~/image.jpg", "rb") as image_file:
encoded_image = base64.b64encode(image_file.read())
raw_params = {'quality':'2','category':'1','debug':'0', 'image': encoded_image}
params = urllib.urlencode(raw_params)
request = urllib2.Request(page, params)
request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")
page = urllib2.urlopen(request)
info = page.info()
Errors:
page = urllib2.urlopen(request)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 444, in error
return self._call_chain(*args)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: Not Found
994
Option 1: Direct File Upload , From this method you can select form-data and set the type to file. Then select an image file by clicking on the button shown in the value column. The content type is automatically detect by postman but if you want you can set it with a relevant MIME type.
Send the image with requests. post(url, files={'image': open('image. jpg', 'rb')}) , see https://requests.readthedocs.io/en/master/user/quickstart/#post-a-multipart-encoded-file. Receive the image with file = request.
Add a this header:
request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")
Also, the image parameter you're sending is a string, not the contents of the image file. You need to b64 encode it
import base64
with open("image.jpg", "rb") as image_file:
encoded_image = base64.b64encode(image_file.read())
then use encoded_image instead of '~/image.jpg' in raw_params
175
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