I've spent the past few hours reading around in here and elsewhere, as well as experimenting, but I'm not really understanding what I am sure is a very basic concept: passing values (as variables) between different functions.
For example, I assign a whole bunch of values to a list in one function, then want to use that list in another function later:
list = [] def defineAList(): list = ['1','2','3'] print "For checking purposes: in defineAList, list is",list return list def useTheList(list): print "For checking purposes: in useTheList, list is",list def main(): defineAList() useTheList(list) main()
Based on my understanding of what function arguments do, I would expect this to do as follows:
However, this is obviously a faulty understanding. My output is:
For checking purposes: in defineAList, list is ['1', '2', '3'] For checking purposes: in useTheList, list is []
So, since "return" obviously does not do what I think it does, or at least it does not do it the way I think it should... what does it actually do? Could you please show me, using this example, what I would have to do to take the list from defineAList() and use it within useTheList()? I tend to understand things better when I see them happening, but a lot of the examples of proper argument-passing I've seen also use code I'm not familiar with yet, and in the process of figuring out what's going on, I'm not really getting a handle on this concept. I'm using 2.7.
ETA- in the past, asking a similar question, it was suggested that I use a global variable instead of just locals. If it will be relevant here also- for the purposes of the class I'm taking, we're not permitted to use globals.
Thank you!
To use global variables between files in Python, we can use the global keyword to define a global variable in a module file. Then we can import the module in another module and reference the global variable directly. We import the settings and subfile modules in main.py . Then we call settings.
As you expect it, Python has also its own way of passing variable-length keyword arguments (or named arguments): this is achieved by using the **kwargs symbol. When using **kwargs, all the keywords arguments you pass to the function are packed inside a dictionary.
This is what is actually happening:
global_list = [] def defineAList(): local_list = ['1','2','3'] print "For checking purposes: in defineAList, list is", local_list return local_list def useTheList(passed_list): print "For checking purposes: in useTheList, list is", passed_list def main(): # returned list is ignored returned_list = defineAList() # passed_list inside useTheList is set to global_list useTheList(global_list) main()
This is what you want:
def defineAList(): local_list = ['1','2','3'] print "For checking purposes: in defineAList, list is", local_list return local_list def useTheList(passed_list): print "For checking purposes: in useTheList, list is", passed_list def main(): # returned list is ignored returned_list = defineAList() # passed_list inside useTheList is set to what is returned from defineAList useTheList(returned_list) main()
You can even skip the temporary returned_list
and pass the returned value directly to useTheList
:
def main(): # passed_list inside useTheList is set to what is returned from defineAList useTheList(defineAList())
You're just missing one critical step. You have to explicitly pass the return value in to the second function.
def main(): l = defineAList() useTheList(l)
Alternatively:
def main(): useTheList(defineAList())
Or (though you shouldn't do this! It might seem nice at first, but globals just cause you grief in the long run.):
l = [] def defineAList(): global l l.extend(['1','2','3']) def main(): global l defineAList() useTheList(l)
The function returns a value, but it doesn't create the symbol in any sort of global namespace as your code assumes. You have to actually capture the return value in the calling scope and then use it for subsequent operations.
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