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I'm learning how to open a file in Python, but when I type the path to the file I want to open, a window pops up, saying "(unicode error) 'unicodeescape codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape". It highlights the first of my parentheses. Here's the code:
with open ("C:\Users\Rajrishi\Documents\MyJava\text.txt") as myfile:
data = myfile.readlines()
print(data)
450
We can solve the issue by escaping the single backslash with a double backslash or prefixing the string with 'r,' which converts it into a raw string. Alternatively, we can replace the backslash with a forward slash.
When we use such a string as a parameter to any function, there is a possibility of the occurrence of an error. Such error is known as Unicode error in Python. We get such an error because any character after the Unicode escape sequence (“ \u ”) produces an error which is a typical error on windows.
A unicode escape sequence is a backslash followed by the letter 'u' followed by four hexadecimal digits (0-9a-fA-F). It matches a character in the target sequence with the value specified by the four digits. For example, ”\u0041“ matches the target sequence ”A“ when the ASCII character encoding is used.
One obvious problem is that you're using a normal string, not a raw string. In
open ("C:\Users\Rajrishi\Documents\MyJava\text.txt")
^^
the \t is interpreted as a tab character, not a literal backslash, followed by t.
Use one of the following:
open("C:\\Users\\Rajrishi\\Documents\\MyJava\\text.txt") # meh
open(r"C:\Users\Rajrishi\Documents\MyJava\text.txt") # better
open("C:/Users/Rajrishi/Documents/MyJava/text.txt") # also possible
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