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How can I open files in a zip archive without extracting them first?
I'm using pygame. To save disk space, I have all the images zipped up. Is it possible to load a given image directly from the zip file? For example: pygame.image.load('zipFile/img_01')
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Python can work directly with data in ZIP files. You can look at the list of items in the directory and work with the data files themselves. This recipe is a snippet that lists all of the names and content lengths of the files included in the ZIP archive zipfile. zip .
To unzip a single file or folder, open the zipped folder, then drag the file or folder from the zipped folder to a new location. To unzip all the contents of the zipped folder, press and hold (or right-click) the folder, select Extract All, and then follow the instructions.
Vincent Povirk's answer won't work completely;
import zipfile archive = zipfile.ZipFile('images.zip', 'r') imgfile = archive.open('img_01.png') ... You have to change it in:
import zipfile archive = zipfile.ZipFile('images.zip', 'r') imgdata = archive.read('img_01.png') ... For details read the ZipFile docs here.
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