Given a 3 times 3 numpy array
a = numpy.arange(0,27,3).reshape(3,3) # array([[ 0, 3, 6], # [ 9, 12, 15], # [18, 21, 24]])
To normalize the rows of the 2-dimensional array I thought of
row_sums = a.sum(axis=1) # array([ 9, 36, 63]) new_matrix = numpy.zeros((3,3)) for i, (row, row_sum) in enumerate(zip(a, row_sums)): new_matrix[i,:] = row / row_sum
There must be a better way, isn't there?
Perhaps to clearify: By normalizing I mean, the sum of the entrys per row must be one. But I think that will be clear to most people.
Broadcasting is really good for this:
row_sums = a.sum(axis=1) new_matrix = a / row_sums[:, numpy.newaxis]
row_sums[:, numpy.newaxis]
reshapes row_sums from being (3,)
to being (3, 1)
. When you do a / b
, a
and b
are broadcast against each other.
You can learn more about broadcasting here or even better here.
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