Here is the code:
from enum import Enum
class EFoo(str, Enum):
A = 'e1'
B = 'e2'
print(EFoo.A)
d = {
EFoo.A : 'eA',
EFoo.B : 'eB'
}
first_key = list(d.keys())[0]
first_key_type = type(first_key)
print("Keys: " + str(d.keys()))
print("Type of first key: " + str(first_key_type))
print("d[EFoo.A] = '" + d[EFoo.A] + "'")
print("d['e1'] = '" + d['e1'] + "'")
Here is the output (Python 3.5)
EFoo.A
Keys: dict_keys([<EFoo.A: 'e1'>, <EFoo.B: 'e2'>])
Type of first key: <enum 'EFoo'>
d[EFoo.A] = 'eA'
d['e1'] = 'eA'
Now the type of the dictionary keys is <enum 'EFoo'>
.
So I don't understand why the code d['e1'] = 'eA'
, which access the dictionary by a string key, works.
Is the string "e1" converted to an "EFoo" instance? Does Python do some reverse lookup to find the correct enum value to convert to?
Moreover, if you remove the str
as a parent of the class, so that the class declaration looks like class EFoo(Enum):
, the above code snippet does not work anymore
What does inheriting from str
exactly do in this case?
EFoo
inherits from str
, so it is a str
-- that is how inheritance works. Because EFoo
inherits from str
all its members are str
s as well as Efoo
s, so standard str
operations work:
>>> isinstance(EFoo.A, str)
True
>>> EFoo.A.upper()
E1
>>> EFoo.A + EFoo.B
e1e2
Inheriting from str
(or any other base type) does remove some of the safeties built in to Enum
, so you should only do it if necessary (such as replacing existing constants of that type already in your code).
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